2x + y + z=5
x + y + 2z =3
3x + 2y + z = 5
motode eliminasi
Jawab:
Penjelasan dengan langkah-langkah:
2x + y + z = 5
x + y + 2z = 3
3x + 2y + z = 5
2x + y + z = 5 (x 1)
x + y + 2z = 3 (x2)
2x + y + z = 5
2x + 2y + 4z = 6 _
- y - 3z = 11
x + y + 2z = 3 (x3)
3x + 2y + z = 5 (x1)
3x + 3y + 6z = 9
3x + 2y + z = 5 _
y + 5z = 4
- y - 3z = 11 (x (-1))
y + 5z = 4 (x1)
y + 3z = - 11
y + 5z = 4 _
-2z = - 15
z = 15/2
z = 7 1/2
y = 4 - 5z
y = 4 - 5(15/2)
y = 4 - (75/2)
y = - 67/2
y = - 33 1/2
x = 3 - y - 2z
x = 3 - (- 67/2) - 2(15/2)
x = 3 + (67/2) - 15
x = 43/2
x = 21 1/2
Tags
Matematika